Chemistry - Eudiometry Question with Solution | TestHub

${\mathrm{C}}_3{\mathrm{H}}_8+{\mathrm{O}}_2\to 100\mathrm{ml}$

Case-I :- Let assume ${\mathrm{C}}_3{\mathrm{H}}_8$ is L.R.

$${\mathrm{C}}_3{\mathrm{H}}_{8(\mathrm{g})}+5{\mathrm{O}}_{2(\mathrm{g})}⟶3{\mathrm{CO}}_{2(\mathrm{g})}+4{\mathrm{H}}_2\mathrm{O}(\mathrm{l})$$

initial ${\mathrm{V}}_1\mathrm{V}2$

final $\begin{array}{lll}0& {\mathrm{V}}_2-5{\mathrm{V}}_1& 3{\mathrm{V}}_1\end{array}$

Vol. contraction $={\mathrm{V}}_{\mathrm{i}}-{\mathrm{V}}_{\mathrm{f}}$

${\mathrm{V}}_{\mathrm{C}}=\left({\mathrm{V}}_1+{\mathrm{V}}_2\right)-\left({\mathrm{V}}_2-5{\mathrm{V}}_1+3{\mathrm{V}}_1\right)$

$45=3{\mathrm{V}}_1$

${\mathrm{V}}_1=15\mathrm{ml}\left({\mathrm{C}}_3{\mathrm{H}}_8\right)$

${\mathrm{V}}_2=85\mathrm{ml}\left({\mathrm{O}}_2\right)$

Case-II :-

Let assume ${\mathrm{O}}_2$ is L.R.

$${\mathrm{C}}_3{\mathrm{H}}_8+5{\mathrm{O}}_2\to 3{\mathrm{CO}}_2+4{\mathrm{H}}_2\mathrm{O}(\ell )$$

Initial ${\mathrm{V}}_1{\mathrm{V}}_2$

Final ${\mathrm{V}}_1-\frac{{\mathrm{V}}_2}{5}0\frac{3}{5}{\mathrm{V}}_2$

Vol. contraction $={\mathrm{V}}_{\mathrm{i}}+{\mathrm{V}}_{\mathrm{f}}$

$V_C=\left(V_1+V_2\right)-\left(V_1-\frac{V_2}{5}+\frac{3}{5}{V}_2\right)$

$45=\frac{3}{5}{\mathrm{V}}_2$

${\mathrm{V}}_2=75\mathrm{ml}$

$V_1=25\mathrm{ml}$