Chemistry - Eudiometry Question with Solution | TestHub

ChemistryEudiometryEudiometric CalculationsMedium2 minQB

ChemistryMediumsingle choice

The percentage by volume of $C_{5} H_{8}$ in a mixture of $C_{5} H_{8}, CH_{4}$ and CO is $51%$ . When 100 ml of the mixture is burnt in excess of $O_{2}$ , the volume of $CO_{2}$ produced is

Options:

Answer:

Solution:

$51 C_{5} H_{8} + x 49 - x CH_{4} + CO O_{2} excess CO_{2}$

POAC on C

$5 \times 51 + x + 49 - x = 1 \times V_{CO_{2}}$

$V_{CO 2} = 255 + 41 = 304$

Stream:JEESubject:ChemistryTopic:EudiometrySubtopic:Eudiometric Calculations

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...