Chemistry - Electrochemistry Question with Solution | TestHub

For the electrochemical cell $\mathrm{Zn}\left|{\mathrm{Zn}}^{2+}\Vert {\mathrm{Cu}}^{2+}\right|\mathrm{Cu}$

$E_{cell}=E_{cell}^{\circ }-\frac{0.059}{2}\log \frac{[{\mathrm{Zn}}^{2+}]}{[{\mathrm{Cu}}^{2+}]}$

$\frac{0.118\times 2}{0.059}=\log \frac{[{\mathrm{Zn}}^{2+}]}{[{\mathrm{Cu}}^{2+}]}$

$\frac{[{\mathrm{Zn}}^{2+}]}{[{\mathrm{Cu}}^{2+}]}=10^{-4}$