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ChemistryElectrochemistryMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasynumerical

The molar conductivity of aqueous solution of a weak acid HA is 200 Scm 2 mol 1 and its pH is 4. What is the value of pK a of HA at 25 o C ?
(Given: λ m o NaA =100 Scm 2 mo1 1 , λ m o HCl =425 Scm 2 mol 1 , λ m o (NaCl)=(125 Scm 2 mo1 1 m o NaA =100 Scm 2 mo1 1 , λ m o HCl =425 Scm 2 mol 1 , λ m o (NaCl)=125 Scm 2 mo1 1 ))

Answer:
4.00
Solution:

M o (HA)= M (HCl)+ M (NaA) M (NaCl)
=425+100125=400 Scm 2 mol 1
pH=4, [H + ]= 10 4 =αC
α= m m = 200 400 =0.5
K a = (Cα)α (1α) = 10 4 (0.5) (1α) = 10 4 , pK a =4

Stream:NTA_ABHYASSubject:ChemistryTopic:ElectrochemistrySubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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