Chemistry - Electrochemistry Question with Solution | TestHub

Discharge: anode ($\mathrm{Pb}$): $\mathrm{Pb}+{\mathrm{SO}}_4^{2-}\to {\mathrm{PbSO}}_4+2e^{-}$ (oxidation). Cathode (${\mathrm{PbO}}_2$): ${\mathrm{PbO}}_2+4{\mathrm{H}}^{+}+{\mathrm{SO}}_4^{2-}+2e^{-}\to {\mathrm{PbSO}}_4+2{\mathrm{H}}_2\mathrm{O}$ (reduction).

Only (A) has the right electrode with the right change.

Answer: (A).