For the cell Zn ( s ) Zn 2 + ( aq ) ∥ M x + ( aq ) M ( s ) , different half cells and their standard electrode potentials are given below: If E Zn 2 + / Zn ∘ = − 0.76 V , which cathode will give a maximum value of E cell 0 per electron transferred?

Zn + 2 Ag + ⟶ 2 Ag + Zn 2 + ( n = 2 e − ) = 0.80 − ( − 0.76 ) = 1.56 V for 2 e ∴ E cell ∘ for 1 e − = 2 1.56 = 0.78 V

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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsHard2 minPYQ_2019

ChemistryHardstatement

For the cell $Zn (s) Zn^{2 +} (aq) ∥ M^{x +} (aq) M (s),$ different half cells and their standard electrode potentials are given below:
If $E_{Zn^{2 +} / Zn}^{\circ} = - 0.76 V,$ which cathode will give a maximum value of $E_{cell}^{0}$ per electron transferred?

Options:

Answer:

Solution:

$Zn + 2 Ag^{+} ⟶ 2 Ag + Zn^{2 +} (n = 2 e^{-})$ $= 0.80 - (- 0.76) = 1.56 V$ for $2 e$ $∴ E_{cell}^{\circ}$ for $1 e^{-} = \frac{1.56}{2} = 0.78 V$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2019

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