Chemistry - Electrochemistry Question with Solution | TestHub

(A) for 0.1 M KCl solution

$$K=\frac{cellconstant}{Resistance}$$

$$Cellconstant=1.29\times 100m^{-1}=129m^{-1}(correct)$$

(B) for 0.02 M KCl solution

$$K=\frac{cellconstant}{Resistance}$$

$$K=\frac{1.29}{520}=0.248\times 10^{-2}{\Omega }^{-1}c{m}^{-1}(correct)$$

(C) for 0.02 M KCl solution

$${\Lambda }_M=\frac{K}{M}=\frac{0.248\times 10^{-2}{\Omega }^{-1}c{m}^{-1}}{0.02mol{L}^{-1}}$$

$${\Lambda }_M=\frac{0.248\times 10^{-2}{\Omega }^{-1}c{m}^{-1}}{0.02\times 1000mol{m}^{-3}}$$

$${\Lambda }_M=124\times 10^{-4}{\Omega }^{-1}{m}^{2}mo{l}^{-1}(correct)$$

(D) correct