Find the Δ G for the process AgCl ( s ) → Ag + ( aq ) + Cl − ( aq ) at 298 K given E ∘ Ag + / Ag = 0.80 V and E ∘ AgCl / Ag / Cl − = 0.22 V .

Question

Find the Δ G for the process AgCl ( s ) → Ag + ( aq ) + Cl − ( aq ) at 298 K given ​ E ∘ Ag + / Ag ​ = 0.80 V and E ∘ AgCl / Ag / Cl ​ − = 0.22 V .

TestHub · Accepted Answer

Concepts Used: Gibbs Free Energy, Cell potential,Silver - Silver Chloride Electrode

Solution:

The reaction is the difference of two half-cells:

1. AgCl + e⁻ → Ag + Cl⁻ ( $Δ G_{1} = - 1 \cdot F \cdot 0.22$ )

2. Ag⁺ + e⁻ → Ag ( $Δ G_{2} = - 1 \cdot F \cdot 0.80$ )

Target: AgCl → Ag⁺ + Cl⁻

$Δ G = Δ G_{1} - Δ G_{2} = F (0.80 - 0.22) = 0.58 \times 96500 \approx 55.97 k J$

Final Answer: Option (A)

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