Chemistry - Electrochemistry Question with Solution | TestHub

Hence, Charge passed =$1.6\times 10^{-19}\times 3\times 6.02\times 10^{23}$

$=1.6\times 3\times 6.02\times 10^4$coulomb.

Number of gram equivalents of Cl₂ formed = $\frac{1.6\times 3\times 6.02\times 10^4}{96500}=3$

The number of moles of Cl₂ formed =$\frac{3}{2}$.

Volume of Cl₂ at NTP = $22.4\times \frac{3}{2}=33.6$ L.