Chemistry - Electrochemistry Question with Solution | TestHub

The Edison Cell is represented as:

$Fe(s)|FeO(s),20\%KOH(aq),N{i}_2{O}_3(s),NiO(s)|Ni(s)$

The correct information related to this cell is/are:

(A) Anode reaction is $\mathrm{Fe}(\mathrm{s})+2{\mathrm{OH}}^{-}($aq. $)\to \mathrm{FeO}(\mathrm{s})+{\mathrm{H}}_2\mathrm{O}(\ell )+2{\mathrm{e}}^{-}$

(B) Cathode reaction is ${\mathrm{Ni}}_2{\mathrm{O}}_3(\mathrm{s})+{\mathrm{H}}_2\mathrm{O}(\ell )+2{\mathrm{e}}^{-}\to 2\mathrm{NiO}(\mathrm{s})+2{\mathrm{OH}}^{-}$(aq.)

(C) ${\mathrm{E}}_{\text{cell }}$ will not change on changing the concentration of KOH solution

(D) $\Delta {\mathrm{G}}^{\circ }$ for the cell reaction is $-96500\times {\mathrm{E}}_{\text{cell }}^0$ per mole of $\mathrm{Fe}(\mathrm{s})$