Chemistry - Electrochemistry Question with Solution | TestHub

At $25^{\circ }\mathrm{C}$, the degree of dissociation of pure water is $1.9\times 10^{-9}$. If the specific conductance of water at this temperature is $\mathrm{x}\times 10^{-6}{\mathrm{Sm}}^{-1}$. Calculate the value of x (Nearest Integer).

Given ionic molar conductances at infinite dilution for ${\mathrm{H}}^{+}$and ${\mathrm{OH}}^{-}$ions are $350\times 10^{-4}$ and $200\times 10^{-4}{\mathrm{Sm}}^2{\mathrm{mole}}^{-1}$ respectively