Calculate standard free energy change for the reaction 2 A g + 2 H + → H 2 + 2 A g + Given: E A g + / A g o = + 0.80 V

E c e l l o = E H 2 o - E A g o = 0 - 0.80 = - 0.80 Δ G ° = - n F E c e l l o = - 2 × 96500 × ( - 0.8 ) = + 154.4 k J

Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

Calculate standard free energy change for the reaction $2 A g + 2 H^{+} \to H_{2} + 2 A g^{+}$

Given: $E_{A g^{+} / A g}^{o} = + 0.80 V$

Options:

Answer:

Solution:

$E_{c e l l}^{o} = E_{H_{2}}^{o} - E_{A g}^{o}$

$= 0 - 0.80 = - 0.80$

$Δ G ° = - n F E_{c e l l}^{o}$

$= - 2 \times 96500 \times (- 0.8)$

$= + 154.4 k J$

Stream:NTA_ABHYASSubject:ChemistryTopic:ElectrochemistrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...