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ChemistryElectrochemistryConductance/conductivity/^mMedium2 minQB

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If cell constant is $0.40 cm^{- 1}$ , the conductivity of 0.015 M NaCl solution having $R = 1850 ohm$ is equal to

Answer:

Solution:

Conductivity ( $κ$ ) of an electrolytic conduction is given by:

$κ = \frac{1}{R es i s t an ce} \times C e ll co n s t an t$

$κ = \frac{0.40}{1850} S c m^{- 1}$

$κ = 2.162 \times 1 0^{- 4} S c m^{- 1}$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: QB

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