Chemistry - Electrochemistry Question with Solution | TestHub

At what $\mathrm{pH}$, given half cell ${\mathrm{MnO}}_4^{-}(0.1\mathrm{M})\mid {\mathrm{Mn}}^{2+}$ $(0.001 \mathrm{M})$ will have electrode potential of $1.282 \mathrm{V}$ ? (Nearest Integer)

Given ${\mathrm{E}}_{{\mathrm{MnO}}_4^{-}/{\mathrm{Mn}}^{2+}}^o=1.54 \mathrm{V},\frac{2.303\mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{V}$