Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryFaraday's Law of Electrolysis/Electrolytic CellsMedium2 minPYQ_2013

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A solution of copper sulphate $(CuSO_{4})$ is electrolysed for $10$ minutes with a current of $1.5$ amperes. The mass of copper deposited at the cathode (at. mass of $Cu = 63 u$ ) is :

Options:

Answer:

Solution:

$W = Zit$ where $Z$ = Electrochemical equivalent Eq. wt. of copper $= \frac{63}{2} = 31.5$ $Z = \frac{31.5}{96500} W = Zit = \frac{31.5}{96500} \times 1.5 \times 10 \times 60 = 0.2938 g$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Faraday's Law of Electrolysis/Electrolytic Cells

⏱ 2mℹ️ Source: PYQ_2013

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