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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryConductance/conductivity/^mMedium2 minQB

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The specific conductivity of $N /10 KCl$ solution at $2 0^{\circ} C$ is $0.0212 ohm^{- 1} cm^{- 1}$ and the resistance of the cell containing this solution at $2 0^{\circ} C$ is 55 ohm . The cell constant is

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Answer:

Solution:

$κ = \frac{1}{R} \times ce ll co n s t an t ⟹ C e ll co n s t an t = κ \times R = 0.0212 \times 55$

$= 1.166 c m^{- 1} .$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: QB

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