Calculate the time required in second to deposit 5.85 g Ni from NiCl 2 solution by passing 10 A current (molar mass of Ni = 58.5 g mol − 1 )

Question

Calculate the time required in second to deposit 5.85 g Ni from NiCl 2 ​ solution by passing 10 A current (molar mass of Ni = 58.5 g mol − 1 )

TestHub · Accepted Answer

The reaction for the deposition of Ni is:

$Ni^{2 +} + 2 e^{-} \to Ni$

Number of moles of Ni deposited $= \frac{5.85}{58.5} = 0.1 mol$

Since $1 mole$ of Ni requires $2 moles$ of electrons, the total charge required is:

$Q = 0.1 \times 2 \times 96500 = 19300 C$

Using the formula $Q = I \times t$ :

$19300 = 10 \times t$

$t = 1930 s$

Answer: $1930$

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