Chemistry - Electrochemistry Question with Solution | TestHub

If $\rho$ is a resistivity and $\kappa$ is conductivity or specific conductance, then $\begin{array}{rl}\kappa & =\frac{1}{\rho };\because \rho =R\times \frac{a}{l}\\ \therefore & \kappa =\frac{1}{R}\times \frac{\ell }{a}{\Omega }^{-1}{m}^{-1}\left(OR{\mathrm{ohm}}^{-1}{\mathrm{m}}^{-1}\text{ or }S{\mathrm{m}}^{-1}\right)\end{array}$ (In C.G.S. system, the units of $\kappa$ are ${\Omega }^{-1}{\mathrm{cm}}^{-1}$ or $\mathrm{S}{\mathrm{cm}}^{-1}$ which are used commonly)