Chemistry - Electrochemistry Question with Solution | TestHub

The reduction reaction of magnesium is given by:

${\text{Mg}}^{2+}+2e^{-}\to \text{Mg}$

From the stoichiometry of the reaction, $1$ mole of Mg requires $2$ moles of electrons, which corresponds to $2\text{ F}$ of electricity.

Number of moles of Mg to be produced = $\frac{\text{Mass}}{\text{Molar mass}}=\frac{8}{24}=\frac{1}{3}\text{ mol}$

Quantity of electricity required = $\frac{1}{3}\times 2\text{ F}=\frac{2}{3}\text{ F}=0.666\text{ F}$

Answer: $0.666$ F