Chemistry - Electrochemistry Question with Solution | TestHub

Limiting Molar Conductivities of Ions:
- $\stackrel{\oplus }{\mathrm{H}}:349.8{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}$
- ${\mathrm{Na}}^{+}:50.11{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}$
- ${\mathrm{K}}^{+}:73.52{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}$
- ${\mathrm{Ca}}^{+2}:119{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}$
- ${\mathrm{Mg}}^{+2}:106.12{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}$
Therefore correct order of limiting molar conductivity of cations will be -
$\stackrel{\oplus }{\mathrm{H}}>{\mathrm{Ca}}^{+2}>{\mathrm{Mg}}^{+2}>{\mathrm{K}}^{+}>{\mathrm{Na}}^{+}$