One Faraday of electricity liberates x × 10 – 1 gram atom of copper from copper sulphate, x is______.

One Faraday of electricity means it is equivalent to one mole of electrons charge. Cu 2 + + 2 e – → Cu 2 Faraday → 1 mol Cu 1 Faraday → 0 . 5 mol Cu deposit 0 . 5 mol = 0 . 5 g atom = 5 × 10 – 1 x = 5

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ChemistryElectrochemistryFaraday's Law of Electrolysis/Electrolytic CellsEasy2 minPYQ_2024

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One Faraday of electricity liberates $x \times 10^{- 1}$ gram atom of copper from copper sulphate, $x$ is______.

Answer:

Solution:

One Faraday of electricity means it is equivalent to one mole of electrons charge.

${Cu}^{2 +} + 2 e^{-} \to Cu$

$2$ Faraday $\to 1 mol Cu$

$1$ Faraday $\to 0.5 mol Cu$ deposit

$0.5 mol = 0.5 g atom = 5 \times 10^{- 1}$

$x = 5$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Faraday's Law of Electrolysis/Electrolytic Cells

⏱ 2mℹ️ Source: PYQ_2024

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