Chemistry - Electrochemistry Question with Solution | TestHub

Electrode potential data are given below:
${\mathrm{Fe}}^{+3}(\mathrm{aq})+{\mathrm{e}}^{-}⟶{\mathrm{Fe}}^{+2}(\mathrm{aq});{\mathrm{E}}^{\circ }=+0.77\mathrm{V}$
${\mathrm{Al}}^{3+}(\mathrm{aq})+3{\mathrm{e}}^{-}⟶{\mathrm{Al}}_{(\mathrm{s})};{\mathrm{E}}^{\circ }=-1.66\mathrm{V}$
${\mathrm{Br}}_2(\mathrm{aq})+2{\mathrm{e}}^{-}⟶2{\mathrm{Br}}^{-}(\mathrm{aq});{\mathrm{E}}^{\circ }=+1.08\mathrm{V}$
Based on the data, the reducing power of ${\mathrm{Fe}}^{2+}$, $\mathrm{Al}$ and ${\mathrm{Br}}^{-}$will increase in the order