Chemistry - Electrochemistry Question with Solution | TestHub

Fe²⁺ + 2e⁻ ⎯→ Fe; $\Delta G_1^{\circ }$

$\frac{F{e}^{3+}+3e^{-}⎯\to Fe;\Delta G_2^{\circ }}{F{e}^{3+}+e^{-}⎯\to F{e}^{2+};\Delta G_3^{\circ }}$

$\Delta G_3^{\circ }=\Delta G_2^{\circ }-\Delta G_1^{\circ }$

$n_{3}F{E}_3^{\circ }=n_{2}F{E}_2^{\circ }-n_{1}F{E}_1^{\circ }$

$E_3^{\circ }=\frac{n_2{E}_2^{\circ }-n_1{E}_1^{\circ }}{n_3}$

$3X_2-2X_1$