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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryConductance/conductivity/^mMedium2 minPYQ_2023

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The molar conductivity of $0.02 M AgI$ at $298 K$ is $142.3 Ω^{- 1} cm^{2} mol^{- 1}$ . What is its conductivity?

Options:

Answer:

Solution:

$\land k k ∴ k = \frac{1000 k}{c} = \frac{Λ c}{1000} = \frac{142.3 Ω ^{- 1} cm ^{2} mol ^{- 1} \times 0.02 mol L ^{- 1}}{1000 cm ^{3} L ^{- 1}} = 2.85 \times 1 0^{- 3} Ω^{- 1} cm^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2023

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