Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryConductance/conductivity/^mHard2 minPYQ_2021
ChemistryHardsingle choice

The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol-1. What is the dissociation constant of acetic acid? Choose the correct option.

λH+∘=350 S cm2 mol-1λCH3COO-∘=50 S cm2 mol-1

NEET 2021

Options:

Answer:
C
Solution:

λCH3COOH∘=λCH3COO-∘+λH+∘

λCH3COO-∘=350+50=400 S cm2 mol-1

λCH3COOH=20Scm2 mol-1 given

α=λCH3COOHλCH3COOH∘=20400=5×10-2

Ka=cα2=0.007×5×10-22=1.75×10-5 molL-1

Stream:NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m
⏱ 2mℹ️ Source: PYQ_2021

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