Chemistry - Electrochemistry Question with Solution | TestHub

Anode Half cell: ${\mathrm{Ni}}_{(\mathrm{s})}\stackrel{\text{ Oxidation }}{⟶}{\mathrm{Ni}}^{2+}+2{\mathrm{e}}^{-}$ Cathode Half-cell, ${\mathrm{e}}^{-}+{\mathrm{Ag}}^{+}\stackrel{\text{ Reduction }}{⟶}{\mathrm{Ag}}_{(\mathrm{s})}$ Reducing Agent is ${\mathrm{Ni}}_{(\mathrm{s})}$