Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryConductance/conductivity/^mHard2 minPYQ_2021

ChemistryHardsingle choice

The molar conductance of $NaCl, HCl$ and ${CH}_{3} COONa$ at infinite dilution are $126.45, 426.16$ and $91.0 {Scm}^{2} {mol}^{- 1}$ respectively. The molar conductance of ${CH}_{3} COOH$ at infinite dilution is. Choose the right option for your answer.

NEET 2021

Options:

Answer:

Solution:

$Λ_{m}^{\infty} ({CH}_{3} COOH) = Λ_{m}^{\infty} ({CH}_{3} COONa) + Λ_{m}^{\infty} (HCl) - Λ_{m}^{\infty} (NaCl)$

$= 91 + 426.16 - 126.45$

$= 390.71 S {cm}^{2} {mol}^{- 1}$

Stream:NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2021

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