Chemistry - Electrochemistry Question with Solution | TestHub

${\mathrm{B}}_2{\mathrm{H}}_6+3{\mathrm{O}}_2\to {\mathrm{B}}_2{\mathrm{O}}_3+3{\mathrm{H}}_2\mathrm{O}$
According to balanced equation
27.66 g${\mathrm{B}}_2{\mathrm{H}}_6$i.e. 1 mole${\mathrm{B}}_2{\mathrm{H}}_6$requires 3 mole of${\mathrm{O}}_2$. Now this oxygen is produced by electrolysis of water as follows
$2{\mathrm{H}}_2\mathrm{O}\stackrel{4\mathrm{F}}{\to }2{\mathrm{H}}_2+{\mathrm{O}}_2$
As 1 mole${\mathrm{O}}_2$is produced by 4 F charge
So 3 mole${\mathrm{O}}_2$will be produced by 12 F charge
So now on applying
Q$=$It
$\text{12}\times \text{965}00\mathrm{C}=100\times \mathrm{t}\left(\mathrm{s}\right)$
$\mathrm{t}=\frac{12\times 96500}{100\times 3600}$hours
$\mathrm{t}=3.2$hours