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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsEasy2 minPYQ_2020

ChemistryEasysingle choice

When 0.1 mol $Mn O_{4}^{2 -}$ is oxidised the quantity of electricity required to completely oxidise $M n O_{4}^{2 -}$ to $M n O_{4}^{-}$ is

(1 F=96500)

Options:

Answer:

Solution:

$\underset{0.1 m o l e}{\overset{+ 6}{M n} O_{4}^{- 2}} \to \overset{+ 7}{M n} O_{4}^{-} + \underset{0.1 mole}{e^{-}}$
charge required $= 0.1 F = 0.1 \times 96500 = 9650$ $C$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2020

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