Chemistry - Electrochemistry Question with Solution | TestHub

For the following electrochemical cell at 298 K,

$\mathrm{P}\mathrm{t}\left(\mathrm{s}\right)\left|{\mathrm{H}}_2\left(\mathrm{g},1\mathrm{ }\mathrm{b}\mathrm{a}\mathrm{r}\right)\right|{\mathrm{H}}^{+}\left(\mathrm{a}\mathrm{q},1\mathrm{M}\right)|\left|{\mathrm{M}}^{4+}\left(\mathrm{a}\mathrm{q}\right),{\mathrm{M}}^{2+}\left(\mathrm{a}\mathrm{q}\right)\right|\mathrm{P}\mathrm{t}\left(\mathrm{s}\right)$

${\mathrm{E}}_{\mathrm{c}\mathrm{e}\mathrm{l}\mathrm{l}}=0.092\mathrm{V}$when$\frac{\left[{\mathrm{M}}^{2+}\left(\mathrm{a}\mathrm{q}\right)\right]}{\left[{\mathrm{M}}^{4+}\left(\mathrm{a}\mathrm{q}\right)\right]}=10^{\mathrm{x}}$

Given:${\text{E}}_{{\text{M}}^{4+}|{\text{M}}^{2+}}^0=0.151\text{V};2.303\frac{\text{RT}}{\text{F}}=\mathrm{0.059 }\text{V}$

The value of x is