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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryConductance/conductivity/^mEasy2 minPYQ_2020

ChemistryEasysingle choice

Molar conductivity of a solution of an electrolyte $A B_{3}$ is $150$ $S c m^{2} m o l^{- 1}$ . If it ionizes as ${AB}_{3} \to A^{3 +} + 3 B^{-}$ , its equivalent conductivity will be

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Answer:

Solution:

$\land_{e q} = [\frac{1}{n^{+} \times Z^{+}}] \land_{m}$
Where, $\land_{m} =$ molar conductance
$n^{+} =$ number of cations
$Z^{+} =$ charge of cation
$\land_{e q} = (\frac{1}{1 \times 3}) \times 150 = 50$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2020

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