Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100Ω . The conductivity of this solution is 1.29 S m − 1 . Resistance of the same cell when filled

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Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100Ω . The conductivity of this solution is 1.29 S m − 1 . Resistance of the same cell when filled with 0.2 M of the same solution is 520Ω . The molar conductivity of 0.02 M solution of the electrolyte will be

TestHub · Accepted Answer

There is one mistake in Question paper. Assuming concentration of solution is 0.2 M instead of 0.02 M . Since resistance of 0.2 M is 520Ω . R K 1.29 ( a ℓ ​ ) R K μ ​ = 100Ω = R 1 ​ ( a ℓ ​ ) = 100 1 ​ ( a ℓ ​ ) = 129 m − 1 = 520Ω , C = 0.2 M = R 1 ​ ( a ℓ ​ ) = 520 1 ​ ( 129 ) Ω − 1 m − 1 = K × V in cm ​ = 520 1 ​ × 129 × 0.2 1000 ​ × 1 0 − 6 m 3 = 520 129 ​ × 0.2 1000 ​ × 1 0 − 6 = 1.24 × 1 0 − 3 = 12.4 × 1 0 − 4 ​

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