Chemistry - Electrochemistry Question with Solution | TestHub

$2{\mathrm{H}}_2\mathrm{O}\to 2{\mathrm{H}}_2+{\mathrm{O}}_2$
One mole of${\text{H}}_{\text{2}}\text{O}$need$\text{2}$moles of${\text{e}}^{-}\text{s}$for electrolysis.
So,$\text{Q}\text{=}\text{I}\text{×}\text{t}$
$\Rightarrow \text{t}\text{=}\frac{\text{Q}}{\text{I}}$
$=\frac{2\times 96500}{2}$
$\therefore \text{t}=96500\text{sec}$