Chemistry - Electrochemistry Question with Solution | TestHub

${\mathrm{Fe}}^{2+}(\mathrm{aq})+{\mathrm{Ag}}^{+}(\mathrm{aq})\to {\mathrm{Fe}}^{3+}(\mathrm{aq})+\mathrm{Ag}(\mathrm{s})$

$\begin{array}{rl}& \Delta {\mathrm{G}}_3^0=\Delta {\mathrm{G}}_1^0+\Delta {\mathrm{G}}_2^0\\ & -3\mathrm{F}(-\mathrm{z})=-2\mathrm{F}(-\mathrm{y})+\Delta {\mathrm{G}}_2{}^0\\ & \Delta {\mathrm{G}}_2^0=3\mathrm{Fz}-2\mathrm{Fy}\end{array}$

Also $\Delta {\mathrm{G}}_2^0=-{\mathrm{nFE}}_{{\mathrm{Fe}}^{+2}/{\mathrm{Fe}}^{t^{43}}}^0$
$\begin{array}{rl}& 3\mathrm{Fz}-2\mathrm{Fy}=-1\mathrm{F}\left({\mathrm{E}}_{{\mathrm{Fe}}^{t^2}/{\mathrm{Fe}}^{43}}^0\right)\\ & {\mathrm{E}}_{{\mathrm{Fe}}^{2+2}/{\mathrm{Fe}}^{t^3}}^0=2\mathrm{y}-3\mathrm{z}\end{array}$
${\mathrm{E}}_{\text{Cell }}^0$ for reaction will be
$\begin{array}{rl}& {\mathrm{E}}_{{\mathrm{Ag}}^{+}/\mathrm{Ag}}^0+{\mathrm{E}}_{{\mathrm{Fe}}^{t^2/\mathrm{Fe}}}^{03}\\ & =\mathrm{x}+2\mathrm{y}-3\mathrm{z}\end{array}$