Chemistry - Electrochemistry Question with Solution | TestHub

On the basis of the information available from the reaction,
$4/3\text{Al}+{\text{O}}_2\to 2/3{\text{Al}}_2{\text{O}}_3\text{;}\text{ΔG}=-827{\text{kJmol}}^{-1}$, the minimum e.m.f. required to carry out electrolysis of$\mathrm{A}{\mathrm{l}}_2{\mathrm{O}}_3$is$(\mathrm{F}=\mathrm{96500 }\mathrm{C}\mathrm{m}\mathrm{o}{\mathrm{l}}^{-1})$