Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2019
ChemistryMediummatching list

Given:
Co3++e-→Co2+;E°=+1.81V
Pb3++2e-→Pb2+;E°=+1.67V
Ce4++e-→Ce3+;E°=+1.61V
Bi3++3e-→Bi;E°=+0.20V
Oxidizing power of the species will increase in the order:

Options:

Answer:
B
Solution:

Higher the value of ERed0; higher will be its oxidizing power.

Hence correct order is Bi+3<Ce+4<Pb+4<Co+3

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells
⏱ 2mℹ️ Source: PYQ_2019

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