Chemistry - Electrochemistry Question with Solution | TestHub

$\begin{array}{l}{\text{2SnCl}}_{\text{2}}\to {\text{SnCl}}_4+\text{Sn}\\ \text{2}\times \text{190}\equiv 261\equiv 119\\ 0.38\equiv 0.261\equiv 0.119\end{array}$
When$0.119\text{g}$Sn deposited then
(i)${\text{SnCl}}_{\text{2}}\left(\text{Consumed}\right)=0.38\text{g}$
${\text{SnCl}}_{\text{2}}\left(\text{Left}\right)=19-0.38\text{=18}\text{.62}\text{g}$
(ii)${\text{SnCl}}_{\text{2}}\left(\text{Formed}\right)=0.261$
$\frac{{\text{W}}_{{\text{SnCl}}_{\text{2}}}}{{\text{W}}_{{\text{SnCl}}_{\text{2}}}}=\frac{18.62}{0.261}=71.34:1$.