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ChemistryElectrochemistryConductance/conductivity/^mEasy2 minPYQ_2020

ChemistryEasysingle choice

Calculate the cell constant if the specific conductance of a solution is 0.2 $o h m^{- 1} c m^{- 1}$ and its conductivity is 0.04 $o h m^{- 1}$ .

Answer:

Solution:

$\begin{array}{l} K = C \times C e l l c o n s t a n t \\ C e l l c o n s t a n t = \frac{K}{C} \end{array}$
$= \frac{0.2}{0.04} = 5 c m^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2020

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