Chemistry - Electrochemistry Question with Solution | TestHub

Degree of dissociation, $\alpha =\frac{{\Lambda }^c}{{\Lambda }^{\infty }}$ where, ${\Lambda }^c$ and ${\Lambda }^{\infty }$ are equivalent conductances at a given concentration and at infinite dilution respectively. $$\Rightarrow \alpha =\frac{8.0}{400}=2\times 10^{-2}$$ From Ostwald's dilution law (for weak monobasic acid) $$\begin{array}{rl}{\mathrm{K}}_{\mathrm{a}}& =\frac{\mathrm{C}{\alpha }^2}{(1-\alpha )}\\ \text{ or }& \mathrm{C}{\alpha }^2\\ & =\frac{1}{32}{\left(2\times 10^{-2}\right)}^2\\ \text{ or }& =1.25\times 10^{-5}\end{array}$$