Chemistry - Electrochemistry Question with Solution | TestHub

(A) $\begin{array}{l}\text{ Conductivity }(\mathrm{k})=\frac{1}{\text{ resistivity }}=\frac{1}{2.5\times 10^{-3}\Omega \mathrm{cm}}=0.4\times 10^3{\Omega }^{-1}{\mathrm{cm}}^{-1}\\ \text{ Molar conductivity }\left({\Lambda }_{\mathrm{m}}\right)=\frac{1000\mathrm{k}}{\mathrm{C}}=\frac{1000{\mathrm{cm}}^3{\mathrm{L}}^{-1}\times 0.4\times 10^3{\Omega }^{-1}{\mathrm{cm}}^{-1}}{0.8\mathrm{mol}{\mathrm{L}}^{-1}}\end{array}$