Chemistry - Electrochemistry Question with Solution | TestHub

$\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{O}\mathrm{O}\mathrm{H}$is weak acid, NaOH is strong base neutralisation produces strong electrolyte$\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{O}\mathrm{O}\mathrm{N}\mathrm{a}$. Thus, conductance C is low in the beginning, increases gradually and slowly till equivalence point and thereafter increases rapidly.