Chemistry - Electrochemistry Question with Solution | TestHub

$\text{AgN}{\text{O}}_3+\text{KCl}\left(\text{aq}\right)\to \text{AgCl}\left(\mathrm{s}\right)+\text{KN}{\text{O}}_3\left(\text{aq}\right)$

Initially there is aq.$\mathrm{K}\mathrm{C}\mathrm{l}$solution now as solution of$\text{AgN}{\text{O}}_3$is added,$\mathrm{A}\mathrm{g}\mathrm{C}\mathrm{l}\left(\mathrm{s}\right)$is formed. Hence conductivity of solution is almost compensated (or slightly increase) by the formation of$\text{KN}{\text{O}}_3$. After end point conductivity increases more rapidly because addition of excess$\text{AgN}{\text{O}}_3$solution.