Chemistry - Electrochemistry Question with Solution | TestHub

$2{\text{HSO}}_4^{-}\to {\text{S}}_2{\text{O}}_8^{2-}+2{\text{H}}^{+}+2{\text{e}}^{-\text{}}$

So, required rate = 1 mol/hr of${\text{S}}_2{\text{O}}_8^{2-}$= 2 moles of${\text{HSO}}_4{}^{-}$

$=\frac{2\times 96500C}{3600s}=\frac{2\times 965}{36}\text{A}\simeq \text{53.6 A}$

So required current$=\frac{4}{3}\times \text{53.6 A}=\text{71.47 A}$