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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryConductance/conductivity/^mEasy2 minPYQ_2020

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The equivalent conductance of a $0 .2 N$ solution of an electrolyte was found to be $200 Ω^{- 1} {cm}^{2} {eq}^{- 1}$ . The cell constant of the cell is $2 {cm}^{- 1}$ . The resistance of the solution is

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Answer:

Solution:

$Λ_{v} = 200 Ω^{- 1} {cm}^{2} {eq}^{- 1}$
$C_{N} = 0.2 N, {cm}^{- 1}$
$K = \frac{Λ_{v} \times C_{N}}{1000} = \frac{200 \times 0.2}{1000 \times 10} = \frac{1}{25} Ω^{- 1} c m^{- 1}$
$R = \frac{1}{K} . \frac{l}{a} = 25 \times 2 = 50 Ω$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2020

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