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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The resistance of $0 .01 N$ solution of an electrolyte was found to be $220 ohm$ at $298 K$ using a conductivity cell with a cell constant of $0.88 cm^{- 1}$ . The value of equivalent conductance of solution is-

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Answer:

Solution:

$Λ_{eq} = k \times \frac{100}{N} = \frac{1}{R} \times \frac{l}{a} \times \frac{1000}{N}$

$= \frac{1}{R} \times cell constant \times \frac{1000}{N}$

$= \frac{1}{220} \times 0.88 \times \frac{1000}{0.01}$

$= 400 mho cm^{2} g e q^{- 1}$

Stream:NTA_ABHYASSubject:ChemistryTopic:ElectrochemistrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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