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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsEasy2 minPYQ_2020
ChemistryEasysingle choice

Zn|ZnSO4(0.01M)||CuSO4(1.0M)|Cuis a Daniel cell. The ‘emf ’ of this cell at 298K isE1. when the concentration ofZnSO4changes to 1.0 M and that ofCuSO4is 0.01 M, the ‘emf ’ changed toE2. What is the relationship betweenE1andE2

Options:

Answer:
B
Solution:

E1=Eo-0.05912log0.011=Eo+0.05912×2
E 2 = E o − 0.0591 2 log 1 0.01 = E o − 0.0591 2 ×2
∴E1>E2.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells
⏱ 2mℹ️ Source: PYQ_2020

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