What is the standard potential of cell Ni Ni 2 + ( 1 M ) ∥ Cu 2 + ( 1 M ) Cu If E ∘ Cu = 0 ⋅ 337 V and E ∘ Ni = − 0 ⋅ 236 V

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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2020

ChemistryMediumsingle choice

What is the standard potential of cell $Ni Ni^{2 +}_{(1 M)} ∥ Cu^{2 +}_{(1 M)} Cu$ If $E^{\circ} Cu = 0 \cdot 337 V$ and $E^{\circ} Ni = - 0 \cdot 236 V$

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Answer:

Solution:

$E_{ceil}^{0} = E_{cuthode}^{0} - E_{anode}^{0} = E_{Cu}^{0} - E_{Ni_{i}}^{0} = 0.337 V - (- 0.236 V) = 0.573 V$

Stream:MHT_CETSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2020

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