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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryFaraday's Law of Electrolysis/Electrolytic CellsMedium2 minPYQ_2019

ChemistryMediumsingle choice

A solution of $N i {(N O_{3})}_{2}$ is electrolyzed between platinum electrode $0.1$ Faraday electricity. How many mole of $N i$ will be deposited at the cathode?

Options:

Answer:

Solution:

$N i^{+ 2} + 2 e^{-} \to N i$
$2 F$ charge gives = 1 mole of $N i$
$0.1 F$ charge gives $= \frac{1}{2} \times 0.1 = 0.05 m o l e N i$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Faraday's Law of Electrolysis/Electrolytic Cells

⏱ 2mℹ️ Source: PYQ_2019

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