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ChemistryElectrochemistryConductance/conductivity/^mHard2 minPYQ_2017
ChemistryHardnumerical

The conductance of0.0015 Maqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinizedPt electrodes. The distance between the electrodes is120 cmwith an area of cross-section of1 cm2. The conductance of this solution was found to be5×10-7S. ThepH of the solution is4. The value of limiting molar conductivity of this weak monobasic acid in aqueous solution is Z × 102S cm-1mol-1.The value ofZ is.

Answer:
6.00
Solution:

For weak acid, H+==c×mcm

=c×k×1000cm=k×1000m=G×la×1000m

10-4=5×10-71201×1000Z×102  Z=6

Stream:JEE_ADVSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m
2mℹ️ Source: PYQ_2017

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