Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsEasy2 minPYQ_2017

ChemistryEasysingle choice

The emf of a particular voltaic cell with the cell reaction $Hg_{2}^{2 +} + H_{2} ⇌ 2 Hg + 2 H^{+}$ is $0.65 V$ . The maximum electrical work of this cell when $0.5 g$ of $H_{2}$ is consumed.

Options:

Answer:

Solution:

$W_{m a x} = - n . FE$ ; $W_{m a x} = - 2 \times 96500 \times 0.65 = - 1.25 \times 1 0^{5} J$ $0.5 g H_{2} = 0.25 mole$ Hence, $W_{m a x} = 1.25 \times 1 0^{5} \times 0.25 = - 3.12 \times 1 0^{4} J$

Stream:VITEEESubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2017

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